some foundational linear algebra
Oct. 29th, 2008 02:43 amLet U be a matrix such that det(U) = 1.
Show that for any square matrix A, the eigenvalues of UA have the same modulus as the eigenvalues of A.
I don't know how to get the eigenvectors of UA from the eigenvectors of A.
Show that for any square matrix A, the eigenvalues of UA have the same modulus as the eigenvalues of A.
I don't know how to get the eigenvectors of UA from the eigenvectors of A.